Make it 0 on one side

x2 - 2x + = 4(x2-2x +1)-3

-3x² +6x -1 = 0

Step-by-step explanation:

x2 - 2x + = 4(x2-2x +1)-3

x² - 2x = 4x²-8x +4 - 3

x²-4x²-2x+8x = 4-3

-3x² +6x = 1

-3x² +6x -1 = 0

Step-by-step explanation:

find the value of y in the second equation

x + y = -2,

but y = -2-x as well

so take the value that we have found for (x) into the first equation

2x + 2(-2-x)= 8

-2x + -4-2x = 8

-4x-4=8

-4x = 12

x=-3,

now just substitute x value into either equation

x + y =-2

-3 + y = -2

y =1