Marcy ran 18 miles on Monday, 3.45 miles on Tuesday,

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cocomelon

10.02.2022

$\begin{aligned} f(n) & = \dfrac{2}{n^2} = 2n^{-2} \\ \\[6pt] f'(n) & = 2(-2)n^{-2-1} & & \text{power rule}\\ & = -4n^{-3} & & \text{notice how this is a choice}\\ \\[6pt] f''(n) & = -4(-3)n^{-4} \\ f''(n) & = -12n^{-4} \end{aligned}$ $\begin{aligned} f(n) & = \dfrac{1}{3n^3} = \dfrac{1}{3}n^{-3} \\[6pt] f'(n) & = \dfrac{-1}{n^4}=-n^{-4} & & \text{notice how this is a choice}\\ \\[6pt]f''(n)& =4n^{-5}=\dfrac{4}{n^5} \end{aligned}$ the question choices are all wrong and you are correct.i think whoever authored the question just did a quick change without checking. notice how the first derivative is a valid choice for both questions.

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Marcy ran 18 miles on Monday, 3.45 miles on Tuesday, and 0.78 miles on Wednesday. How far did Marcy run in all?

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