Mary Sue was a dedicated company employee. She worked for the same company for 32 years (1986 to 2018). Mary Sue once noted “When I started working here in 1986, I was making $20,000.
Now I’m making about $60,000!”
a) By what percent has Mary Sue’s salary increased over the years?
b) Inflation from 1986 to 2018 was about 130%, meaning increase $1 in 1986 by 130% to get its
equivalent value in 2018:
130% of $1: $1(1.3) = $1.30
Increase by 130%: $1 + $1.30 = $2.30.
So, $1 in 1986 has the same value as $2.30 in 2018.
Knowing this, what might someone say was Mary Sue’s “true” percent increase in salary over
the years? (i.e., what is her percent salary increase when adjusted for inflation?).

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

L,M,N are midpoints altitude to ac

Step-by-step explanation:

If the slope is parallel m1=m2=-3

eqn of line is

y-y1=m(x-x1)

y-2=-3(x-3)

y-2=-3x+9

3x+y=11