Math practice Comparing and Ordering Integers Practice and Problem Solving: A/B please i need help

    Part 1

Given equation:

C(t) = -0.30 (t – 12)² + 40  

For t = 0

C(t) = -0.30 (0 - 12)² + 40

C(t) = -0.30 (-12)² + 40

C(t) = -3.2

For t = 12 (noon)

C(t) = -0.30 (12 - 12)² + 40

C(t) = -0.30 (0)² + 40

C(t) = 40

For t = 24 (midnight)

C(t) = -0.30 (24 - 12)² + 40

C(t) = -0.30 (12)² + 40

C(t) = -0.30 × 144 + 40

C(t) = - 43.2 + 40

C(t) = -3.2

Part 2

attached below

Part 3

C(t) = –0.30(t – 12)² + 40

F(t)=9/5C(t)+32

Substituting the values:

F(t)=9/5{–0.30 (t – 12)² + 40}+32

F(t) = -0.54 (t – 12)² + 72 + 32

F(t) = -0.54 (t – 12)² + 104

5, 6 and 7, should be simplish

good luck, i hope this helps :)

Step-by-step explanation: