(matrix) addiction and subtraction of a matrix calculate:

Ответ:

kellylopez7829

07.01.2022

See explanation

Step-by-step explanation:

When we add or subtract matrices with the same dimensions, we simply add or subtract corresponding elements.

$A+B+C\\ \\=\left(\begin{array}{ccc}2&0&-1\\-4&1&3\end{array}\right)+\left(\begin{array}{ccc}0&-1&2\\5&0&6\end{array}\right)+\left(\begin{array}{ccc}-7&5&-2\\-6&-9&-11\end{array}\right)\\ \\=\left(\begin{array}{ccc}2+0+(-7)&0+(-1)+5&-1+2+(-2)\\-4+5+(-6)&1+0+(-9)&3+6+(-11)\end{array}\right)\\ \\=\left(\begin{array}{ccc}-5&4&-1\\-5&-8&-2\end{array}\right)$

$A-B-C\\ \\=\left(\begin{array}{ccc}2&0&-1\\-4&1&3\end{array}\right)-\left(\begin{array}{ccc}0&-1&2\\5&0&6\end{array}\right)-\left(\begin{array}{ccc}-7&5&-2\\-6&-9&-11\end{array}\right)\\ \\=\left(\begin{array}{ccc}2-0-(-7)&0-(-1)-5&-1-2-(-2)\\-4-5-(-6)&1-0-(-9)&3-6-(-11)\end{array}\right)\\ \\=\left(\begin{array}{ccc}9&-4&-1\\-3&10&8\end{array}\right)$

$A+B-C\\ \\=\left(\begin{array}{ccc}2&0&-1\\-4&1&3\end{array}\right)+\left(\begin{array}{ccc}0&-1&2\\5&0&6\end{array}\right)-\left(\begin{array}{ccc}-7&5&-2\\-6&-9&-11\end{array}\right)\\ \\=\left(\begin{array}{ccc}2+0-(-7)&0+(-1)-5&-1+2-(-2)\\-4+5-(-6)&1+0-(-9)&3+6-(-11)\end{array}\right)\\ \\=\left(\begin{array}{ccc}9&-6&3\\7&10&20\end{array}\right)$

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(matrix) addiction and subtraction of a matrix

calculate:
a) a+b+c
b) a-b-c
c) a+b-c

Ответ:

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(matrix) addiction and subtraction of a matrix calculate: a) a+b+c b) a-b-c c) a+b-c

Ответ:

Ответ:

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(matrix) addiction and subtraction of a matrix

calculate:
a) a+b+c
b) a-b-c
c) a+b-c