Mde=123°and mbc=55°. find ma. the figure is not drawn to scale
a.34°
b.95.5°
c.68°
d.89°

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)

Part 3)

Part 4)

Part 5) Is a exponential growth function

Part 6)

Part 7)

Part 8)  

Part 9) Is a exponential growth function

Part 10)   or  

Part 11)  

Part 12)

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

The slope is equal to

The y-intercept or initial value is

so

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

For x=120 months

substitute in the linear equation

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

For x=24 months

substitute in the linear equation

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

substitute in the formula above

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

 Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

 where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

substitute in the formula above

Applying property of exponents

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

   or  

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years