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Becky323
27.06.2019 •
Mathematics
Me. explanation needed in algebraic form: a painting, square in shape, is placed in a wooden frame with width of 10% of the length of the side of the painting. the painting was enlarged by 10%. by what percent is the new frame bigger than the original frame if the width of the frame remains the same?
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Ответ:
the new frame is bigger than the original frame by 10%
Step-by-step explanation:
Let the length of the original frame be l,
then it's width is (10% of l)=
×l
=![\frac{l}{10}](/tpl/images/0024/3803/c67ed.png)
hence area of original frame=A=length×width
=![\frac{l^{2} }{10}](/tpl/images/0024/3803/e77a1.png)
now the length of frame is enlarged by 10%
new lenght of frame=l+10%×l
=l+
×l
=
×l
width of new frame==![\frac{l}{10}](/tpl/images/0024/3803/c67ed.png)
area of new frame=length×width
=![\frac{11l^{2} }{100}](/tpl/images/0024/3803/8eb41.png)
percent change=((area of new frame-area of old frame)×100)÷area of old frame
=10%
Ответ: