Mathematics: Me! the question is in the attachment

Me! the question is in the attachment - id4412855, klanclos1620

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amykookie24

14.01.2022

The answer is D

The way to do is to subtract corresponding item with the same form of A(i,j), in other words, the item with same row and column

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ladybugperez05

07.10.2021

Mathematics

Refresh if you see errorsthe instantaneous rate of change of $g$ at a point is given by the value of the derivative function $g'$ at that point.derivatives are the instantaneous rate of change (same as the slope of a tangent line at a point).the question wants you to find $g'(2)$ .to do that, we need to find an equation for $g'(x)$ .differentiate the function $g(x)=\frac{1}{3}x^6+4x-7$ with respect to x.recall that the power rule for derivatives is as follows: $\dfrac{d}{dx}(x^n) = nx^{n-1}$ so differentiating: $\begin{aligned} g'(x)& =\left(\frac{1}{3}x^6+4x-7\right)' \\ & =\left(\frac{1}{3}x^6\right)'+(4x)'-\left(7\right)' \\ & =\left(\frac{1}{3} \cdot 6 \cdot x^5\right)+4-0 \\ & =\frac{6}{3}x^5+4\\ & =2x^5+4\\ \end{aligned}$ substituting x=2 $\begin{aligned} g'(2) & = 2(2)^5+4 \\ & = 68 \end{aligned}$ the instantaneous rate of change of the function at x=2 is 68.

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Me! the question is in the attachment

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