Me with my pre-cal! a population of bacteria is growing according to the equation p(t)=800e^0.13t. use a graphing calculator to estimate when the population will exceed 1474. t=?me! so much.

when is

1474  = 800e^0.13t.

/800     /800

1.8425 = e^0.13t.

ln 1.8425  =  ln e^0.13t.  (us natural lg LN on your calc)

ln 1.8425  =   0.13t  ln e  (ln e is 1)

ln 1.8425  =   0.13t

/0/13               /0.13

ln 1.8425/0.13  = t

answer is number of years

in your calc type

(ln(1.8425))/0.13

umm can you please send a pic or somthing to explain this and I will help you right away??

Step-by-step explanation: