Mathematics: Measured in meters, the wavelength of red light is about 8*10^-7, and the wavelength of violet light is 4*10^-7. the wavelength of red light is how many times longer than the wavelength of violet light?

Okay, so use substitution.x + y+ 10 = 0y = -x -10I just moved things around so you can substitute y in.x^2+y-2=0x^2+(-x-10)-2=0x^2-x-10-2=0x^2-x-12=0(x-4)(x+3)=0x=4,-3This is answer choice B....

Measured in meters, the wavelength of red light

Ответ:

Robinlynn228

17.01.2022

Mathematics

The wavelength of red light is 2 times longer than the wavelength of violet light.

Step-by-step explanation:

Let be "x" the number of times the wavelength of red ligth is longer than the wavelength of violet light.

Knowing that the wavelength (measured in meters) of red light is about $8*10^{-7}$ and the wavelength (measured in meters) of violet light is $4*10^{-7}$ , you have to:

Divide the wavelength of red light (measured in meters) by the wavelength of violet light (measured in meters).

Then:

$x=\frac{wavelength\ of\ red\ light}{wavelength\ of\ violet\ light}\\\\x=\frac{8*10^{-7}}{4*10^{-7}}$

Remember the Quotiend of powers property:

$\frac{b^m}{b^n}=b^{(m-n)}$

Then:

x=2

The wavelength of red light is 2 times longer than the wavelength of violet light.

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Measured in meters, the wavelength of red light is about 810^-7, and the wavelength of violet light is 410^-7. the wavelength of red light is how many times longer than the wavelength of violet light?

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