kev71
26.08.2021 •
Mathematics
Meena's age is four times her daughter's age. Two years ago she was five times herdaughter's age. Find their present ages. pls explain step by step
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Ответ:
8 and 32
Step-by-step explanation:
let daughter's age be x then Meena's age is 4x
2 years ago daughter's age was x- 2 and Meena's age was 4x - 2
Meena was 5 times her daughter's age then , so
4x - 2 = 5(x - 2)
4x - 2 = 5x - 10 ( subtract 4x from both sides )
- 2 = x - 10 ( add 10 to both sides )
8 = x
Thus
daughter is 8 years and Meena is 4 × 8 = 32 years
Ответ: