Mega middle school sells wrapping paper to raise money for student activities the school keeps half of all sales $300 prizes to top sellers how much wrapping paper must be sold for the school to earn $5000

Step-by-step explanation:

Let the total sales for wrapping paper be represented by variable x

Amount the school keeps is half of total sales x, minus $300. Written as an equation, that would be ; 0.5x - 300

If the schools wants to earn $5000, this amount would be equal to the above equation of what it keeps;

0.5x - 300 = 5000

add 300 to both sides;

0.5x = 5000+300

0.5x = 5300

divide both sides by 0.5 and solve for x;

x=5300 / 0.5

x= 10,600

Therefore, they need to sell $10,600 worth of wrapping paper.

a.) 4x = 2(x + 14)

b.) Measure of A = 56°

    Measure of B = 56°

Step-by-step explanation:

We know that,

When two lines are crossed by another line transversal line , the angles in matching corners are called corresponding angles.

Also,

When two lines are parallel then the Corresponding Angles are equal.

Given that,

A = 4x and B = 2(x+14).

i.e.

∠A = 4x and ∠B = 2(x+14)

a.)

Now,

As A and B are parallel

So,

∠A = ∠B

⇒4x = 2(x + 14)                  

(This is the equation that represent the corresponding angle relationship between A and B.)

b.)

Now,

⇒4x = 2x + 2(14)

⇒4x = 2x + 28

⇒4x - 2x = 28

⇒2x = 28

⇒x = 14

So,

we get

∠A = 4(14)

      = 56

⇒∠A = 56°

and

∠B = 2(14 + 14)

     = 2(28)

     = 56°

⇒∠B = 56°

∴ we get

Measure of A = 56°

Measure of B = 56°