Mathematics: Mis the midpoint of cf for the points of c(4,2) and f(6,10). find mf

Mis the midpoint of cf for the points of c(4,2) and

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j1theking18

04.01.2022

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad F(\stackrel{x_2}{6}~,~\stackrel{y_2}{10}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ M = \left( \cfrac{6+4}{2}~~,~~\cfrac{10+2}{2} \right)\implies M=(5,6) \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ M(\stackrel{x_1}{5}~,~\stackrel{y_1}{6})\qquad F(\stackrel{x_2}{6}~,~\stackrel{y_2}{10})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ MF = \sqrt{(6-5)^2+(10-6)^2}\implies MF=\sqrt{1^2+4^2} \\\\\\ MF=\sqrt{17}\implies MF \approx 4.12$

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Ответ:

emmeaw245

27.04.2023

Mathematics

The power of the root of the power of a variable can be written as a rational power by creating a rational exponent that is the product of the powers divided by the root. The rational exponent should be reduced to lowest terms. For example, the seventh power of the sixth root of the fifth power of x will be x^(7*5/6) = x^(35/6).
hope it helps

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Mis the midpoint of cf for the points of c(4,2) and f(6,10). find mf

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