Motorcycle travel 90 mph accelerates to pass a truck five seconds later the car is going 120 mph calculate the acceleration

Explanation:

Let Vc be the velocity of the car and I'm the velocity of the motorcycle. If we convert their given values, we get:

Vc = 87 km/h * 1000m / 1km * 1h / 3600s = 24.17m/s

Vm = 95 km/h * 1000m / 1km * 1h / 3600s = 26.38m/s

Since their positions are equal after 17s we can stablish that:

Where d is the initial separation distance of 54m. Solving for a, we get:

  Repacing the values:

P(x<10) =0

Step-by-step explanation:

M =1/μ

M= 1/15 =0.066667

X- Exp (0.066667)

Where: X is the random variable for number of days

P (X<x) = 1 - e^-mx

P(X - x) = 1 - e^-0.06666 x10

P(x<10) = 0