Mr. and Mrs. Jones live in a neighborhood where the mean family income is $45,000 with a standard deviation of $9,000. Mr. and Mrs. Smith live in a neighborhood where the mean is $100,000 and the standard deviation is $30,000. What is the relative dispersion of the family incomes in the two neighborhoods

Jones(20%), Smiths(30%)

Step-by-step explanation:

The relative dispersion of a data set is the ratio of its standard deviation to its arithmetic mean.

Mr. and Mrs. Jones' neighborhood mean family income is $45,000 with a standard deviation of $9,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

9000:45000

1:5

Expressed as a Percentage: (1/5)x100=20%

The Relative Dispersion of the family incomes in Mr. and Mrs. Jones' neighborhood is 20%

Mr. and Mrs. Smith's neighborhood mean family income is $100,000 and the standard deviation is $30,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

30000:100000

3:10

Expressed as a Percentage: (3/10)x100=30%

The Relative Dispersion of the family incomes in Mr. and Mrs. Smith's neighborhood is 30%

$7.31

Step-by-step explanation:

30j+40% + 25j= 562.8

30j+25j= 55j

55j + 40% = 562.8

40% of 55 is 22

77j = 562.8

562.8 77 = 7.309090909

Simplify 7.309090909

$7.31 Per hour.