Mr.Lee is shopping for a new electric water heater. Brand A costs $586 and uses 444 kilowatt-hours per month. Brand B costs $639 and uses 377 kilowatt-hours per month. If electricity costs $0.17 per kilowatt-hour, how much would Mr.Young save on electricity per month by buying brand B?

mr.young would save 11.39 per month on buying brand b

Step-by-step explanation:

0.17×444=75.48

0.17×377=64.09

75.48-64.09=11.39

option D

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

y=Arc cos (1/3x)    ;  -5≤x≤5

The answer is option D