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Isaiahplater27
14.07.2019 •
Mathematics
Mrs. rifkin has 84 oranges. 24 of her oranges were rotten. the rest were either ripe or unripe. there were 18 more ripe oranges than unripe oranges. find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.
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Ответ:
Alright, lets get started.
Suppose there were x unripe oranges.
there were 18 more ripe oranges than unripe oranges
Means number of ripe oranges = x + 18
There were 24 rotten oranges too.
So, the sum of all oranges will be =![x + (x + 18) + 24](/tpl/images/0086/6361/4384f.png)
So, the sum of all oranges will be =![2 x + 42](/tpl/images/0086/6361/52078.png)
As per given in question, sum of total oranges are 84.
Hence making them equal
Subtracting 42 from both sides
Dividing 2 in both sides
x = 21
Means number of unripe oranges = 21
Means number of ripe oranges = 21 + 18 = 39
Number of rotten oranges = 24
the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges =
: Answer
Hope it will answer :)
Ответ:
As you can see in the denominator, the values keep on multiplying by 2, meaning that the number must multiply by 0.5 or 1/2 to get the next one.
So the rule is *1/2.