Mutating die 1, 2, 3, 4, 6,8 8 on six faces. a) If no on top odd, all odd no's on die are doubled
) b) if no on top is even even no's on die are halved and new die is rolled,
same rules applied again to create 3rd die When 3rd die rolled, what is probability that a 2 will be on top face?

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