malikvanison

18.08.2020 •

Mathematics

Natalie and Kaiden baked a strawberry cake in their culinary arts class. They baked the cake in a rectangular pan with dimensions 4 inches×6 inches . Natalie and Kaiden decide to share the cake evenly by cutting in half along the diagonal from one corner of the pan to the other.

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Ответ:

23ricorvan

28.12.2020

Mathematics

The correct option is A

Step-by-step explanation:

From the question we are told that

The population is $\mu = 6.6$

The level of significance is $\alpha = 5\% = 0.05$

The sample data is 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is $H_o : \mu = 6.6$

The Alternative hypothesis is $H_a : \mu 6.6$

The critical value of the level of significance obtained from the normal distribution table is

$Z_{\alpha } = Z_{0.05 } = 1.645$

Generally the sample mean is mathematically evaluated as

$\=x = \frac{\sum x_i }{n}$

substituting values

$\=x = \frac{9.0 + 7.3 + 6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}$

$\=x = 7.5571$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum [ x - \= x ]}{n} }$

substituting values

$\sigma = \sqrt{\frac{ [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }$ $\sigma = 1.1774$

Generally the test statistic is mathematically evaluated as

$t = \frac{\= x - \mu } { \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{7.5571 - 6.6 } { \frac{1.1774 }{\sqrt{7} } }$

t = 1.4274

Looking at the value of t and $Z_{\alpha }$ we see that $t < Z_{\alpha }$ hence we fail to reject the null hypothesis

What this implies is that there is no sufficient evidence to state that the sample data show as significant increase in the average birth rate

The conclusion is that the mean is $\mu = 6.6 \ lb$

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