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machucagm01
24.03.2020 •
Mathematics
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Ответ:
Пошаговое решение:
Разделите на высшую знаменательную силу 'n'
так
так как
также
Следовательно
∵![\lim _{n\to \infty \:}\left(\frac{2n-3}{5+4n}\right)=\frac{1}{2}](/tpl/images/0561/1711/620b3.png)
Пошаговое решение:
Разделите на высшую знаменательную силу 'n²'
так как
и
так
∵![\lim _{n\to \infty \:}\left(\frac{4n^2-3n+5}{7-2n^2}\right)=-2](/tpl/images/0561/1711/ce325.png)
5.1)
Пошаговое решение:
Положил x = 1
∵![\lim _{x\to \:1}\left(\frac{4x-2}{2x^2+3x+7}\right)=\frac{1}{6}](/tpl/images/0561/1711/2acc3.png)
2)
Пошаговое решение:
Решить
так как
так
Итак, уравнение:
Положил x = 1
∵![\lim _{x\to \:1}\left(\frac{2x^2-5x+3}{x^2-1}\right)=-\frac{1}{2}](/tpl/images/0561/1711/ea91c.png)
3)
Пошаговое решение:
так как
и
так
4)
Пошаговое решение:
Apply L'Hopital's Rule
Положил x = 0
5)
Пошаговое решение:
Check the attached diagram for the solution of this question.
(Проверьте прилагаемую диаграмму для решения этого вопроса.)
Ответ:
7 It is correct.
8