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jayqq4240

23.11.2021

Mathematics

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

= 11 × 8

= 88 square units

Area of trapezoid OGEF = $\frac{1}{2}(b_1+b_2)\times h$

= $\frac{1}{2}(\text{GE+OF)}\times (\text{OG})$

= $\frac{1}{2}(3+6)\times 4$

= 18 units²

Area of trapezoid GCDE = $\frac{1}{2}(\text{GC+DE)}\times (\text{GE})$

= $\frac{1}{2}(7+2)\times 3$

= 13.5 units²

Area of triangle AFH = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(5)(2)$

= 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

= 88 - (18 + 13.5 + 5)

= 88 - 36.5

= 51.5 units²

Therefore, area of the given polygon is 51.5 units²

What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3

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