Need answers to both questions

-4c+12

all real numbers

Step-by-step explanation:

6) 28-(3c+4) =2 (c+6)+c

When there is a - in front of an expression in parentheses , change the sign of each term of the expression.

28-3c-4=2(c+6)+c

Distribute 2 through the parentheses

28-3c-4=2c+12+c

Now we do the same thing only different way

2(c+6)

Multiply each term in the parentheses by 2

2c+2×6

Multiply the numbers

2c+12

28-3c-4=2c+12+c

subtract the numbers

24-3c=2c+12+c

Collect like terms

24-3c=3c+12

It's the same thing only different way ok

2c+c

If a term doesn't have a coefficient , it is considered that the coefficient is 1.

2c+1c

Collect like terms by adding their coefficients

(2+1)c

Add the numbers

3c

24-3c=3c+12

Move variable to the left hand side and change its sign

24-3c-3c=12

Move constant to the right  by adding its opposite to both sides

-3c-3c+24-24=12-24

eliminate the opposites

-3c-3c=12-24

Collect like terms

-6c=12-24

Calculate the difference

-6c=-12

so the same thing only different way ok

12-24

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger.

-(24-12)

Subtract the numbers

-12

-6c=-12

divide both sides of the equation by -6

-6c÷(-6)=-12÷(-6)

Any expression divided by itself equals 1

c=-12÷(-6)

Dividing two negatives equals a positive

(-)÷(-)=(+)

c=12÷6

Calculate the quotient

c=2

Answer : 2

7) no solution

.8

.35

.04

.3

.75

.625     or .63

.66

.11

.57