Need with these 3 questions explain how you do it. thx!

1. Observe that the f(t) is change by 4 per time t => there's a acceleration of 4 => f''(t) = 4;  Take the derivative of it we can get a velocity function. f'(t) = 4t + c. Since the velocity from 100 to 80 is -20 (average), this means at t = 0, f'(0) = -22 => f'(t) = 4t - 22; Take the derivative again to get the position function: f(t) = 2t^2 - 22t + d, here d = 100 should be trivial. So, the function that models the relationship is    f(t) = 2t^2 - 22t + 100.

2. By the compound interest formula:
    A = P (1 + r/n)^(nt) , since it's yearly, so n = 1;
    results A(t) = 100 (1+0.12)^t.

3. The average rate of change is basically finding the slope, m = y1 - y2 / x1 - x2.

G. -5/2

Step-by-step explanation:

First we want to distribute the 6 into q and 3.

6q + 18 = 2(q + 4)

Next distribute the 2 into q and 4.

6q + 18 = 2q + 8

Now the variable needs to be on one side of the equation. Subtract 2q from  both sides.

4q + 18 = 8

Isolate the variable. Subtract 18 from both sides.

4q = -10

Divide 4 on both sides.

q = -10/4

We can now simplify this even further. Divide -10/4 by 2/2

q = -5/2