Needed asap
a relation is plotted as a linear function on the coordinate plane starting at point c (0,−1)(0,−1) and ending at point d (2,−11)(2,−11) . what is the rate of change for the linear function and what is its initial value? select from the drop-down menus to correctly complete the statements.the rate of change is -11, -5, 0, 5.and the initial value is -11, -2, -1, 0.

The rate of change for your linear function is the slope.  You can use the points C and D to calculate it. 
slope = (y2 - y1)/(x2 - x1) = (-11 - (-1))/(2 - 0) = -10/2 = -5
I'm not sure what is meant by initial value, but maybe you are looking for the y-intercept of the line.

The y-intercept is the point where the line crosses the y axis, so where x = 0.  You have that because your line passes through the point (0, -1).  When x = 0, y = -1.

This is the answer
Uh it has to be 20 characters long for me to give you the pic so here