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antonio9768
07.03.2020 •
Mathematics
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night (USA Today, April 30, 2012). Assume that room rates are normally distributed with a standard deviation of $55.a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?b. What is the probability that a hotel room costs less than $140 per night (to 4 decimals)?c. What is the probability that a hotel room costs between $200 and $300 per night (to 4 decimals)?d. What is the cost of the 20% most expensive hotel rooms in New York City? Round up to the next dollar.
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Ответ:
a) We can find the z score for the value of 225 and we got:
And we can find this probability with the complement rule:
b)![z = \frac{140-204}{55}=-1.164](/tpl/images/0537/8139/c2df0.png)
And we can find this probability using the normal standard table or excel and we got:
c)![P(200](/tpl/images/0537/8139/f2aa0.png)
And we can find this probability with this difference:
And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.
d) For this part we want to find a value a, such that we satisfy this condition:
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the costs of a population, and for this case we know the distribution for X is given by:
Where
and ![\sigma=55](/tpl/images/0537/8139/49ff6.png)
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
We can find the z score for the value of 225 and we got:
And we can find this probability with the complement rule:
Part b
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the normal standard table or excel and we got:
Part c
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference:
And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.
Part d
For this part we want to find a value a, such that we satisfy this condition:
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
Ответ:
21.0234 and 21.0235