Mathematics: Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school. Sakura walks at 1.4 m/s and takes 20 minutes to get to school. What is the difference between the distances they walked?

ITS ok false alarm my baby was worried but i am ok and i am hereStep-by-step explanation:...

Nichol walks at a constant pace of 1.2 m/s and

gmedisa08

27.07.2021

The difference between the distances they walked is 600 meters.

Step-by-step explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

d = v*t

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

$d_{n} = 1.2 m/s*15min*\frac{60 s}{1 min} = 1080 m$

And the distance traveled by Sakura is:

$d_{s} = 1.4 m/s*20 min*\frac{60 s}{1 min} = 1680 m$

Hence, the difference between the distances they walked is:

$d_{t} = d_{s} - d_{n} = 1680 m - 1080 m = 600 m$

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

I hope it helps you!

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