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star296
20.08.2020 •
Mathematics
Nswer two questions about Systems A AA and B BB: System A AA start text, end text System B BB { − 3 x + 12 y = 15 7 x − 10 y = − 2 ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ −3x+12y=15 7x−10y=−2 { − x + 4 y = 5 7 x − 10 y = − 2 ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ −x+4y=5 7x−10y=−2 1) How can we get System B BB from System A AA? Choose 1 Choose 1 (Choice A) A Replace one equation with the sum/difference of both equations (Choice B) B Replace only the left-hand side of one equation with the sum/difference of the left-hand sides of both equations (Choice C) C Replace one equation with a multiple of itself (Choice D) D Replace one equation with a multiple of the other equation
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Ответ:
(Choice C) C Replace one equation with a multiple of itself
Step-by-step explanation:
Since system A has the equations
-3x + 12y = 15 and 7x - 10y = -2 and,
system B has the equations
-x + 4y = 5 and 7x - 10 y = -2.
To get system B from system A, we notice that equation -x + 4y = 5 is a multiple of -3x + 12y = 15 ⇒ 3(-x + 4y = 5) = (-3x + 12y = 15).
So, (-x + 4y = 5) = (1/3) × (-3x + 12y = 15)
So, we replace the first equation in system B by 1/3 the first equation in system A to obtain the first equation in system B.
So, choice C is the answer.
We replace one equation with a multiple of itself.
Ответ:
there is no image
Step-by-step explanation: