Mathematics: On a certain map , 3 inches represents 15 miles. briarwood and middletown are 15 inches apart on map.what is actual distance between briarwood and middletown? a 25 min b 30 min c 50 min d 75 min

Radius of the circle = 5.5 ydThe area of the given figure. We know that, = Using 3.14 for π, we have Using for π,Therefore, the area of the semi-circle is ....

On a certain map , 3 inches represents 15 miles.

Ответ:

emocow

22.02.2023

Mathematics

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Radius of the circle "" = 5.5 yd

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The area of the given figure.

$\sf \bf {\boxed {\mathbb {SOLUTION :}}}$

$\implies {\blue {\boxed {\boxed {\purple {\sf {b. \:47.5\:sq\:yd.}}}}}}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}$

We know that,

$\sf\pink{Area\:of\:a\:semi-circle}$ = $\frac{\pi \: {r}^{2} }{2}$

Using 3.14 for π, we have

$= \frac{3.14 \times ( {5.5 \: yd})^{2} }{2} \\$

$= \frac{3.14 \times 5.5 \times 5.5 \: {yd}^{2} }{2}\\$

$= \frac{94.985 \: {yd}^{2} }{2} \\$

$= 47.5 \: {yd}^{2} \\$

Using $\frac{22}{7}$ for π,

$= \frac{22 \times 5.5 \times 5.5 \: {yd}^{2} }{7 \times 2} \\$

$= \frac{665.5 \: {yd}^{2} }{14}\\$

$= 47.5 \: {yd}^{2} \\$

Therefore, the area of the semi-circle is $47.5\: yd²$ .

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}$

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On a certain map , 3 inches represents 15 miles. briarwood and middletown are 15 inches apart on map.what is actual distance between briarwood and middletown?
a 25 min
b 30 min
c 50 min
d 75 min

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