On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)

Given:

A curved line with a minimum value of (-1,-2), crosses the x-axis at (-2, 0) and the y-axis at (0, 0).

To find:

x-intercepts of the function.

Solution:

The curved line passes through the points (-1,-2), (-2,0) and (0,0).

We know that, y-coordinate is zero at x-intercepts.

From the given points, only (-2,0) and (0,0) have 0 as y-coordinate.

So, x-intercepts of the function are (-2,0) and (0,0).

Therefore, the correct options are 1 and 3.

x>-4

Step-by-step explanation:

First you factor the left side which makes the equation (x+4)(x-1)>0. Then you set both to 0, which would make it x+4>0 and x-1>0. Solve both equations and you get x>-4 and x>1. They overlap, so you can just say that the answer is x>4