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kayyaybruh
23.10.2020 •
Mathematics
On a coordinate plane, a line goes through (negative 3, negative 4) and (3, 0). What are the necessary criteria for a line to be perpendicular to the given line and have the same y-intercept? The slope is Negative three-halves and contains the point (0, 2). The slope is Negative two-thirds and contains the point (0, −2). The slope is Three-halves and contains the point (0, 2). The slope is Negative three-halves and contains the point (0, −2).
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Ответ:
The slope is Negative three-halves and contains the point (0, −2).
Step-by-step explanation:
Did it on edge 2020
Ответ:
Therefore, we conclude that correct answer is: The slope is
and contains the point
.
Step-by-step explanation:
From Analytical Geometry we remember that slopes of two lines that are perpendicular to each other observe the following relationship:
Where:
At first we must determine the slope of original line by definition of secant line:
Where:
If we know that
and
, the slope of original line is:
In addition, the standard form of original line is represented by this formula:
Where
is the y-Intercept of original line, dimensionless.
If we get that
,
,
, then y-Intercept of the line is:
From (Eq. 1) we get that slope of perpendicular line is:
The slope of perpendicular line is
.
And we procced to use the equation of perpendicular line in standard form is:
If we know that
,
and
, the value of
is:
Therefore, we conclude that correct answer is: The slope is
and contains the point
.
Ответ:
Explanation:
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