On your wedding day you leave for the church 30 minutes before the ceremony is scheduled to start. The church is only 10 miles away, but you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 15 minutes is only 5 miles per hour. What average speed do you need to go for the rest of the trip to get to the church on time

You need to have an average speed of at least 35 miles per hour for the rest of the trip to get to the church on time

Step-by-step explanation:

We use the following relation to solve the question:

In which v is the velocity, d is the distance, and t is the time.

First 15 minutes:

Time of 15 minutes = 0.25 hour, so

Velocity of 5 miles per hour. So the distance is of:

Final 15 minutes:

The will need to drive 10 - 1.25 = 8.75 miles in 15 minutes = 0.25 hours. So, the average speed will need to be of at least:

You need to have an average speed of at least 35 miles per hour for the rest of the trip to get to the church on time

AB = 19

AD = 38

Step-by-step explanation:

It appears that C is the midpoint of BD, so because of that we know that BC and CD are equal. If CD is 9.5, then BD is also 9.5

If B is the midpoint of AD, then we know that AB and BD are equal. So, we can first find the length of BD by adding BC and CD, which equals 19. BD = 19

Because AB = BD and BD = 19, we know that AB would also equal 19.

AB = 19

Then you can just add AB + BD to get AD

19 + 19 = 38

Hope this helps! I apologize if I get this answer incorrect.