Mathematics: One cylinder has a volume that is 8 cm less than a of the volume of a second cylinder. If the first cylinder s volume is 216 cm? what is the correct equation and value of x, the volume of the second cylinder?x+8-216; x = 182 cm-8-2167 - 196 cmcoll+8-216-238cmcol-8-216-256 cmNacks and otumSave and ExitSave and Exit

0.5Step-by-step explanation:you divide 20÷40=0.5...

One cylinder has a volume that is 8 cm less than

Ответ:

parkerwallace04

28.01.2022

Corrected Question

One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder. If the first cylinder’s volume is 216cm³, what is the correct equation and value of x, the volume of the second cylinder?

The equation is: $216=\frac{7}{8}x-8$

Volume of the second cylinder= 256cm^3

Step-by-step explanation:

Volume of the first cylinder= 216cm^3

Let the volume of the second cylinder=x

7/8 of the volume of a second cylinder= $\frac{7}{8}x$

8 less than 7/8 of the volume of a second cylinder= $\frac{7}{8}x-8$

Therefore, the equation is:

$216=\frac{7}{8}x-8$

Next, we solve for x

$216=\frac{7}{8}x-8\\216+8=\frac{7}{8}x\\224=\frac{7}{8}x\\$Cross multiply\\7x=224*8\\Divide both sides by 7\\x=256cm^3$

The volume of the second cylinder is 256cm^3

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