christopherandp66l91
04.01.2021 •
Mathematics
One hour after a hiker left camp, a biker set out to catch up. If the hiker traveled 3 miles per hour and the biker traveled 6 miles per hour faster, how long will it take for the biker to catch up with the hiker?
Solved
Show answers
More tips
- L Legal consultation What Documents Are Required for a Russian Passport?...
- S Sport How to Choose Tennis Rackets?...
- H Health and Medicine AKDS Vaccination: Ensure Your Child s Safety...
- H Health and Medicine Naskol ko Opasen Ukus Kleshcha i Kak Ego Raspoznat...
- C Computers and Internet How to Delete Your Account on Odnoklassniki...
- H Health and Medicine What to Do When Your Jaw Locks Up?...
- G Goods and services What Are the Most Popular Services?...
- P Philosophy How did the concept of module arise in computer science?...
Answers on questions: Mathematics
- M Mathematics Pls helpppp find x and y plsss...
- C Chemistry Even though water evaporates from the surface, the earth has water and is not dried out. what step to bring water back to earth. which one is correct explain how and why (a) condensation...
- M Mathematics Answer for 7 and 8 and explanation if possible...
- M Mathematics Please help! I need it to move on to the next question I have 30 minutes...
- H History What reason(s) did the Framers give for their decision to write out a declaration?...
Ответ:
30 minutes after biker left
Step-by-step explanation:
Given that :
Speed of hiker = 3 mph
Speed of biker = (3 +6) = 9 mph
Present Distance of hiker when the biker set out ;
Present Distance of hiker = speed * time = (3 * 1) = 3 miles
Time taken to catchup equals :
Present distance + (distance when biker set out) = bikers distance
Let time taken = x
(3 + (3 * x)) = (9 *x)
(3 + 3x) = 9x
3 + 3x = 9x
3 = 9x - 3x
3 = 6x
x = 3/6
x = 1/2 hours
x = 30 minutes
30 minutes after biker left
Ответ: