Mathematics: One hundred grams of radium are stored in a container. the amount r of radium present after t years can modeled by r=10e^-0.00043t. after how many years will only 5 grams of radium be present? round your answer to the nearest whole year.

One hundred grams of radium are stored in a container.

Ответ:

18sofia18

14.03.2022

Using this equation, we get that it would take 1612 years for only 5 grams to be present.

Substituting 5 for R, we have
$5=10e^{-0.00043t}$

Dividing both sides by 10,
$\frac{5}{10}=\frac{10e^{-0.00043t}}{10}
\\
\\0.5=e^{-0.00043t}$

Taking the natural log of both sides, we have
$\ln{0.5}=\ln{e^{-0.00043t}}
\\
\\ \ln{0.5}=-0.00043t$

Dividing both sides by -0.00043, we have
$\frac{\ln{0.5}}{-0.00043}=t
\\
\\1611.9=t
\\
\\1612\approx t$

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Ответ:

julih74

20.03.2021

Mathematics

It's -15 hope this helped!!

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One hundred grams of radium are stored in a container. the amount r of radium present after t years can modeled by r=10e^-0.00043t. after how many years will only 5 grams of radium be present? round your answer to the nearest whole year.

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