One question simple please help

Step-by-step explanation:

Standard equation of a line is y = mx + b, where m is the slope.

Given line y = - 3x + 78, slope, m₁ = -3

To find the line perpendicular to the given line.

The lines are perpendicular to each other if the product of their slopes = - 1

That is,

         

So the slope of new line is

                                                   

First fine the slope.
How?
2 random points and plug them in the slope formula.
In this case :
(-3,0)(0,4) —> 4-0/0-(-3) = 4/3 <— slope
The y intercept is the point where x equals 0
In this case :
(0,4) —> 4 is the y-Intercept
Now, plug in for the equation y= mx + b ( m = slope and b = y intercept)
y = 4/3x + 4
Hope I helped:)