PART A
A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 5 1/5
square yards. The height of each parallelogram is 1 4/5
yards.
PART B
What is the area of the smallest rectangle of wall that the mirror could fit on?

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Ответ:

Mangolinux7173

21.04.2021

Mathematics

This is a system of equations. We know that if L is length, L=x+5, and area=L*w, where w=x. So, 2+5x=(x+5)x therefore 2+5x=x^2+5x. Subtracting 5x from both sides, x^2=2, therefore x=sqrt(2). So, the width is sqrt(2) and length=sqrt(2)+5

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PART A A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 5 1/5 square yards. The height of each parallelogram is 1 4/5 yards. PART B What is the area of the smallest rectangle of wall that the mirror could fit on?