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maddigrace3
21.07.2019 •
Mathematics
Part a: factor 5x2b2 + 14xb2 − 3b2. show your work. part b: factor x2 − 18x + 81. show your work. part c: factor x2 − 121. show your work.
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Ответ:
We have the following expression:
5x2b2 + 14xb2 - 3b2
Rewriting we have:
b2 (5x2 + 14x - 3)
b2 (5x-1) (x + 3)
Part B:
We have the following expression:
x2 - 18x + 81
Rewriting we have:
(x-9) (x-9)
(x-9) ^ 2
Part C:
We have the following expression:
x2 - 121
Rewriting we have:
(x-11) (x + 11)
Ответ:
Part A: b2 (5x-1) (x + 3)
Part B: (x-9) ^ 2
Part C: (x-11) (x + 11)
Step-by-step explanation:
Ответ:
S S S
S S B
S B S
S B B
B B B
B B S
B S B
B S S