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antbanks3050
31.10.2019 •
Mathematics
"part a: solve −np − 70 < 40 for n. show your work."
"part b: solve 4w − 7k = 28 for k. show your work."
i get confused with these types of questions . someone !
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Ответ:
Ответ:
Given :Cost function :![C(x)=7.6x + 10,800](/tpl/images/0246/8870/ef195.png)
To Find : Find the average cost per item when the required number of items is produced
Solution:
a) 200 items
Cost function :![C(x)=7.6x + 10,800](/tpl/images/0246/8870/ef195.png)
Substitute x = 200
So, Total cost of producing 200 items is 12320
Now Average cost per item =![\frac{\text{Total cost}}{\text{No. of items}}](/tpl/images/0246/8870/3ead4.png)
Average cost per item=![\frac{12320}{200}](/tpl/images/0246/8870/a82e3.png)
Average cost per item=61.6
So, the average cost per item when 200 items are produced is 61.6 .
b) 2000 items
Cost function :![C(x)=7.6x + 10,800](/tpl/images/0246/8870/ef195.png)
Substitute x = 2000
So, Total cost of producing 2000 items is 26000
Now Average cost per item =![\frac{\text{Total cost}}{\text{No. of items}}](/tpl/images/0246/8870/3ead4.png)
Average cost per item=![\frac{26000}{2000}](/tpl/images/0246/8870/4cdf2.png)
Average cost per item=13
So, the average cost per item when 2000 items are produced is 13.
c) 5000 items
Cost function :![C(x)=7.6x + 10,800](/tpl/images/0246/8870/ef195.png)
Substitute x = 5000
So, Total cost of producing 5000 items is 48800
Now Average cost per item =![\frac{\text{Total cost}}{\text{No. of items}}](/tpl/images/0246/8870/3ead4.png)
Average cost per item=![\frac{48800}{5000}](/tpl/images/0246/8870/86b42.png)
Average cost per item=9.76
So, the average cost per item when 5000 items are produced is 9.76