ashleybarrera2000
10.12.2020 •
Mathematics
Paul has one rectangular section of wrapping paper left. The perimeter of the paper is 14 feet. The length is two feet more than twice the width. Find the length (x) and width (y) of the wrapping paper.
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Ответ:
idk
Step-by-step explanation:
Ответ:
h(x-1)=4x-7
Step-by-step explanation:
Given :
h(x)=4x-3
Now,
putting the value of x =x-1
h(x-1)=(4(x-1)-3)
h(x-1)=4x-4-3
h(x-1)=4x-7
Answer will be h(x-1)=4x-7