Pedro was curious if circles a and b with x and y Being on a circle respectively with similar so he tried to math one figure onto the other using rigid transformation

The strategy Pedro tend to do isn't worth, because using rigid transformation to place on figure onto the other won't prove that those figures are similar, but it would prove if they are congruent.

Remember that similarity is about proportionality between dimensions of those figures, so it's not about congruence. That means the figures won't match when we place one onto the other.

To prove similarity, Pedro should divide each pair of corresponding coordinate, if all divisions give the same result, that means those figures are similar.

If points ABCD are all on one face then it would be a square. If points are at furthest angles away ie) the length of the prism then to cut through would be the same as first one as all points indicate the ABCD lines even if they are joined . So the answer is a square. We have seen cross sections length ways and if this is the case which is not advised for algebraic term for sq^3 formula, but nevertheless if length ways we could say it has cut a rectangle.

Step-by-step explanation:

We call this for advanced Maths cross sectional area function we find a direction and enter a disk cross section to figure out a limit of integration. So why would we wish to cut through horizontally on a rectangle anyway? IS my point it helps to stay perpendicular to the awkward lengths as we can determine more awkward shapes this way by cutting through the square And show on diagram a central square also..