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malikapooh124
03.10.2019 •
Mathematics
Peed of plane a = 415 mph. speed of plane b = 375 mph. both planes leave from new york city at the same time. plane a flies due north. plane b flies due south. after 4 hours, how far is plane a from plane b (to the nearest mile)?
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Ответ:
Hence, distance between Plane A and Plane B is:
3160 m.
Step-by-step explanation:
It is given that:
Speed of Plane A = 415 mph.
Speed of Plane B = 375 mph.
Now Both planes leave from New York City at the same time. Plane A flies due North and Plane B flies due South.
This means that Plane A and Plane B travels in the opposite directions.
So the distance between them keep on increasing with respect to time.
We know that:
Distance=Speed×Time.
The distance covered by Plane A in 4 hours=415×4=1660 m.
The distance covered by Plane B in 4 hours=375×4=1500 m.
Hence, distance between plane A and Plane B in 4 hours=1660+1500
=3160 m.
Ответ:
And that is the answer.