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Gearyjames8
25.02.2020 •
Mathematics
Peter the optician sees 16 patients one Tuesday.4 are neither short nor long sighted,the total number of short sighted patients is 2 more than the total number of long sighted,how many patients can be short sighted, how many long sighted, and how many will require varifocal lenses
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Ответ:
Solution:
Number of patients having neither long nor shortsightedness = 4
Let number of patients having long sightedness be "x"
The total number of short sighted patients is 2 more than the total number of long sighted
Therefore,
Number of patient having shortsightedness = x + 2
Peter the optician sees 16 patients one Tuesday
Total number of patients = 16
Therefore,
x + x + 2 + 4 = 16
2x + 6 = 16
2x = 16 - 6
2x = 10
x = 5
Number of patients having longsightedness = x = 5
Number of patient having shortsightedness = x + 2 = 5 + 2 = 7
Patients requiring varifocal lenses will be = 5 + 7 = 12
Ответ: