Mathematics: physics convention 11 companies set up equal sized square booths in a row along one wall of a convention center.The booths are adjacent to each other and a 2-ft wide walkway surrounds the block of booths on three sides. The total area of the booths and walkway is 1200 ft^2. What is the side length of each booth?

physics convention 11 companies set up equal sized

markyyy53

03.02.2022

Side length of each booth is 8.35 ft approximately.

Step-by-step explanation:

There are 11 companies set up equal sized square booths in a row along one wall of a convention center.

Now, refer the diagram to answer the problem.

It is given area is 1200.

So, length x width =1200

(11x+24)(x+2)=1200

Multiply using FOIL method.

$11x^{2}$ +22x+24x+48=1200

$11x^{2}$ +46x+48-1200=0

$11x^{2}$ +46x-1152=0

Solve using quadratic formula

x= $\frac{-46+/- \sqrt{46^{2}-4(11)(-1152 } }{2(11)}$

x= $\frac{-46+/-\sqrt{2116+50688} }{22}$

x= $\frac{-46+/-\sqrt{52804} }{22}$

Simplify it

$x=\frac{-49+/- 229.79}{22}$

Simplify to get two values for x.

x=8.35; x=-12.67

Here negative does not work.

Side length of each booth is 8.35 ft.

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