Please answer the question below! Write the equation of a line in standard form that has a slope of ¾ and crosses through the point (8, 4)?

y=3/4x-2

Step-by-step explanation:

The first thing you would do is you would get a graph.

Now write down the point (8,4) (remember to label)

Remember (8,4) is where x is 8 and y is 4

A slope of 3/4 is also known as rise/run. This means in this problem you would rise 3 and move to the right 4. If the slope were negative you would do the opposite direction. For example -1/2 would be go down one move right four.

*You should graph points above and below your point

After that you would go from the point (8,4) and rise 3 and move over to the right 4. This gives you the point (12,7).

Write down that point.

Next you would do another point. So that means you could go down 3 and move 4 to the left which gives you the point, (4,1)

*I recommend having more than two points, but only two points are needed to make a line.

Now you can find the y-intercept with your graph and put it on your equation.

if you want to do it without a graph you need to know this formula.

y=mx+b where m is the slope and b is the y intercept.

Next, put in the equation what you already know so m=3/4.

That give you y=3/4x+b

Next, to find the y intercept plug in the point (8,4). This way you can find the y intercept.

this gives you: 4=3/4(8)+b

Solve for b.

b=-2 so that your y intercept.

So your equation is: y=3/4x-2.

*I recommend checking my work, but this is what I got.

Hope this helped!