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jessica94866

28.08.2020

Mathematics

$\sqrt{ x^{2} } = / x /,$ where / x / is "the absolute value of x";
Then $\sqrt{3 x^{2} } = \sqrt{3} / x / ;$
In ihe same way, $\sqrt{3 x^{4} } = \sqrt{3} / x^{2} / = \sqrt{3} x^{2} ,$ because $x^{2} \geq 0 ;$ ;
The square root of (3x^2) times 3 times the square root of (3x^4) is 9 × / x /

× $x^{2}$ ;But, for x > 0, | x | = x ; for x < 0, | x | = –x ;
Finally, The square root of (3x^2) times 3 times the square root of (3x^4) is 3 $x^{3}$ , for $x \geq 0$ and -3 $x^{3}$ , for $x\ \textless \ 0 .$

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