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hvvhvc

22.12.2022

Mathematics

0.9575465

Step-by-step explanation:

Let the random variable X is normally distributed with mean $\mu=50$ and standard deviation $\sigma=7$ .

Using the formula , $z=\dfrac{x-\mu}{\sigma}$ , we have the z-value for x= 34

$z=\dfrac{34-50}{7}\approx-2.29$

For x= 63

$z=\dfrac{63-50}{7}\approx1.86$

P-value : P(34<x<63)=P(-2.29<z<1.86)

=P(z

Hence, the required probability = 0.9575465

Assume the random variable x is normally distributed with meanmu equals 50μ=50and standard deviation

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