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m∠A + m∠B = m∠B + m∠C  

Example: Δ ABC is isosceles at B

⇒ m∠A = m∠C

⇔ m∠A + m∠B = m∠B + m∠C  

So:  m∠A + m∠B = m∠B + m∠C ⇒ m∠A = m∠C

P/s: sorry, my writing skill is not very good, but u can use the above ideas to write

Ok done. Thank to me :>

The second number = 30

The first number = 25

The third number = 50

Step-by-step explanation:

Let

The second number = x

The first number = x - 5

The third number = 2(x - 5)

Total = 105

105 = x + (x - 5) + 2(x - 5)

105 = x + x - 5 + 2x - 10

105 = 4x - 15

105 + 15 = 4x

120 = 4x

x = 120/4

x = 30

The second number = x

= 30

The first number = x - 5

= 30 - 5

= 25

The third number = 2(x - 5)

= 2(30 - 5)

= 2(25)

= 50