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sotocindy023

08.04.2020

Mathematics

Given that the sample mean is μ=74 and sample standard deviation σₓ= $\frac{σ}{ \sqrt{n}} =\frac{12}{\sqrt{36}} =2$ .

Thge Z- score is $Z=\frac{76.8-74}{2} =1.4$ .

Now we use the Z-score to calculate the required probability.

Refer to standard normal distribution table.

The required probability is

P(X76.8) =P(Z1.4)=1-P(Z

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