PLEASE HELP!!
ILL GIVE MORE POINTS TO THE FASTEST ANSWER

It’s really easy do not make it complicated on yourself!

Fist thing you should know ANY NUMBER WHICH IS TO POWER ZERO THE ANSWER WILL ALWAYS BE ONE!!

Part A : (7^2)^x is (49)^x

(49)^x = 1 , here is basically asking you what’s the value of X to know which number to the power of 49 to put so that it equals to 1, obviously the answer is 0 as we said before ANY NUMBER TO THE POWER OF 0 , the answer will be 1

Part A = 0
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Part B IS GONNA BE WAY EASIER NOW TRUST ME!!

(7^0) = 1

(1)^x = 1

So now is asking what number to put for x for you to multiply by one to get one it’s obviously 1, because 1 x 1= 1

Part B = 1
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I hope you understand my explanation so good luck and best of wishes!!

(i) 2/7 or 0.2857 of the time

(ii) 70 days

Step-by-step explanation:

(i) There are two possible conditions, two bulbs working or one bulb working. The long run fraction of time that there is exactly one bulb working is given by   the expected time with one light bulb working divided by the expected time with one or two bulbs working:

The long-run fraction of time that there is exactly one bulb working is 2/7 or 0.2857 of the time.

(ii) The expected time between light bulb replacements is the expected time for both bulbs to go out:

The expected time between replacements is 70 days.