Please help. In △BAC, draw:

CM is a median
AJ is an angle bisector
CY is an altitude

Please help.

In △BAC, draw:
CM is a median
AJ is an angle bisector
CY is an altitude

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Ответ:

miya214

06.02.2020

Mathematics

Step-by-step explanation: Given that,

$(-9,-3)~\textup{and}~(-12,-4)$ are two points contained in the function. Since it is a direct variation function, so it is a straight line passing through the given points.

Let, $x_{1}=-9,~y_{1} =-3,~x_{2}=-12~\textup{and}~y_{2} =-4.$

So, slope of the line is given by

$m=\dfrac{y_{2}-y_{1} }{x_{2} -x_{1} } \\\Rightarrowc=\dfrac{1}{3}.$

The equation of the line or the function is

$y-y_{1} =m(x-x_{1} )\\\Rightarrow y+3 =\frac{1}{3}(x+9 )\\\Rightarrow3y+9=x+9\\\Rightarrow3y=x\\\Rightarrow y=\frac{x}{3}.$

Thus, (c) $y=\dfrac{x}{3}$ is the correct option.

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Please help. In △BAC, draw: CM is a median AJ is an angle bisector CY is an altitude